Biomechanics MCQ
Biomechanics
Based on the displacement vector u(u_x, u_y) given in #6, {u_x = (a-1)X + 2bY and u_y = 2(a-1)X+bY where a = 1.001 and b = 0.002} linearized strains are e_XY = 1/2(dux/dy + duy/dx)
Based on the displacement vector u(u_x, u_y) given in #6, {u_x = (a-1)X + 2bY and u_y = 2(a-1)X+bY where a = 1.001 and b = 0.002} linearized strains are e_XY = 1/2(dux/dy + duy/dx)
Based on the displacement vector u(u_x, u_y) given in #6,
{u_x = (a-1)X + 2bY and u_y = 2(a-1)X+bY
where a = 1.001 and b = 0.002}
linearized strains are
e_XY = 1/2(dux/dy + duy/dx)
A. 0.001
B. 0.002
C. 0.003
D. 0.004
Answer: C
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